skrf.util.HomoDict.filter

HomoDict.filter(**kwargs)

Filter self based on kwargs

This is equivalent to:

>>> h = HomoDict(...)
>>> for k in kwargs:
>>>     h = h[k ==kwargs[k]]
>>> return h

prefixing the kwarg value with a ‘!’ causes a not equal test (!=)

Examples

>>> h = HomoDict(...)
>>> h.filter(name='jean', age = '18', gender ='!female')